What is the Number?

This riddle challenges your logical thinking and understanding of basic number relationships. Given that the second digit is four times the third, and the first digit is three less than the second, you can set up simple algebraic equations to solve it. Let's denote the three digits as A (first), B (second), and C (third). According to the riddle: - B = 4 × C - A = B - 3 Since these are digits, they must be between 0 and 9. Starting with C, find a digit so that B (4 times C) is also a single digit (0-9). Testing values: - If C=1, B=4 (valid) - If C=2, B=8 (valid) - If C=3, B=12 (invalid, as B must be a single digit) So, valid options are C=1 or 2. For C=1: A = 4 - 3 = 1, so the number is 1 (A), 4 (B), 1 (C) which is 141. For C=2: A = 8 - 3 = 5, so the number is 5 (A), 8 (B), 2 (C) which is 582. Both satisfy the conditions given in the riddle. This type of exercise helps improve problem-solving skills and number sense, which are essential for math learning and exams. I found this riddle useful when tutoring students, as it combines algebra and logical reasoning in a simple yet engaging way. Try creating similar riddles with your own conditions to further enhance mental math abilities and enjoy learning!