🐍 Daily Python Problem: Solve the classic FizzBuzz! 💖

Let's face the legendary FizzBuzz problem! This problem seems simple, but it is popular to use in interviews to see how well we understand Conditional Logic and Loops principles! ✨

Problem: Write the fizz _ buzz (n) function that will return a list of results from 1 to n according to the following rules:

• If that number is divisible by 3 (with a remainder of 0)\ rightarrow, use the word "Fisz."

• If that number is divisible by 5, use the word "Buzz."

• If the number is divisible by both 3 and 5, use the word "FizzBuzz."

• If you do not enter any conditions, use that number as usual.

🌟 Key Tips and 2 Solutions

1.Check order (very important!):

• We need to check the most complicated conditions (divisible 3 and 5 or num% 15 = = 0) before checking the sub-conditions (divisible 3 or divisible 5)! Because if we check divisible 3 first, the number divisible by 15 will be changed to "Fizz" and will never be able to enter the "FizzBuzz" condition again!

2. Solution (2 code patterns):

• Basic (Use If / Elif / Else): This method is straightforward. Use elif so that when you enter any conditions, you will not check any other conditions. Make sure the answer is correct in order.

• "Per String" Choice: This method does not need to check 15 first! We just create a string for free and use output _ string + = "Fizz" if 3 is divisible and output _ string + = "Buzz." If 5 is divisible, if the string is still empty (not in any condition), then use a number!

Example:

• Input: fizz _ buzz (15)

• Output: [1, 2, "Fizz," 4, "Buzz," "Fizz," 7, 8, "Fizz," "Buzz," 11, "Fizz," 13, 14, "FizzBuzz"]

It's a really good problem to practice Logic! Let's take both to practice writing! Keep going. 🥰

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